Why voltage source is being short circuited

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Is the case same for Current SOurce? Debdut Full Member level 3. Go on, try it. If you short a current source you still get the current source current. So a perfect 1A current source will deliver 1A whatever the load - zero or 1M ohm. A real current source will not be quite as good. Debdut said:. Click to expand Similar threads C.

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That means the voltage source is no more - its shorted after all. You can't short two terminals and still say they have a potential difference. What about real life batteries which involve internal resistances? Surely there is some contradiction there? All the short does is drive a current through the resistor which consumes the potential in KVL. But still at the instant of the short, for an ideal battery, if the battery's potential has gone to zero, why is there a current?

If there is a current, then the battery hasn't gone to zero and KVL is violated. What now? This is a very subtle point. During the initial transient phase when the battery potential hasn't become zero, there is a changing current since the potential, as per our earlier discussion, is changing to comply with being called shorted.

Since we have shorted the circuit, there now exists a current loop. The changing current causes a changing magnetic flux in this loop. As per Faraday's law this induces an emf in the circuit which is equal and opposite to the battery's potential, at that time. Its not just that Kirchhoff's law is violated it outright fails, in this transient phase.

When electromagnetic induction is involved, its inadequate and Faraday's law needs to be used. A real life and simultaneously theoretic case of this subtlety is shorting of a charged linear capacitor. Even though the cap's voltage isn't zero over a finite time, KVL is violated at all times. Sign up to join this community. The best answers are voted up and rise to the top.

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